Cheers!

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Forum thread: Power Seller College Newbie ]]>

Cheers!**

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Forum thread: Power Seller College Newbie ]]>

Well let me tell you all about my self.

I am a fun loving, cheerful girl who takes every responsibility seriously, loves watching movies, reading books and playing games on PS3.

Umm, well I guess thats sufficient for the time being,

Lemme know about you all :)

Thank you for reading

Lysco Chimney

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Forum thread: Newbie Lysco Chimney here..:)) ]]>

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Forum thread: Elem Algebra ]]>

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Forum thread: Elem Algebra ]]>

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Forum thread: Upper Level Courses ]]>

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Forum thread: Elem Algebra ]]>

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Forum thread: Calculus II ]]>

Steve

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Forum thread: Calculus II ]]>

The truth is that the vertical line marked with the vertical scale is not the y-axis, but x=-1.69.

The query "y=5+3x, x from 0 to 10" will result in a single graph that appears to show a line through the origin, but in this case the horizontal line marked with the horizontal scale is not the x-axis, but y=5.

Although I recognize that graphs often do not show the axes, I'd like a soft introduction for my developmental students.

How do we force W|Alpha to put the "AxesOrigin" at (0,0)?

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Forum thread: Elem Algebra ]]>

1/(2+cos(x))

at W|Alpha, you get a couple of things worthy of discussion. The first is that both graphs appear to drop below the x-axis (which would be surprising for a function that is always positive), until you notice that the horizontal line showing the scale is not the x-axis at all but y = 0.4.

The fun part for Calculus is that, because the given continuous function is positive everywhere, its anti-derivative is increasing (and differentiable) for all values of x. However, the given expression for the indefinite integral (in W|Alpha or any other CAS using the Risch algorithm) is periodic: f(x + 2pi) = f(x).

And no continuous periodic function is increasing everywhere.

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Forum thread: Calculus II ]]>

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Forum thread: Calculus I ]]>

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Forum thread: Calculus I ]]>

http://www54.wolframalpha.com/input/?i=Piecewise%5B%7B%7B1%2Cx%3C0%7D%2C%7B2%2Cx%3E0%7D%7D%5D

and then it can do integrate, etc, using this

but there should be better way….

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Forum thread: Calculus I ]]>